3.9 \(\int \frac {\csc ^5(x)}{i+\cot (x)} \, dx\)

Optimal. Leaf size=28 \[ -\frac {1}{3} \csc ^3(x)+\frac {1}{2} i \tanh ^{-1}(\cos (x))+\frac {1}{2} i \cot (x) \csc (x) \]

[Out]

1/2*I*arctanh(cos(x))+1/2*I*cot(x)*csc(x)-1/3*csc(x)^3

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Rubi [A]  time = 0.04, antiderivative size = 28, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {3501, 3768, 3770} \[ -\frac {1}{3} \csc ^3(x)+\frac {1}{2} i \tanh ^{-1}(\cos (x))+\frac {1}{2} i \cot (x) \csc (x) \]

Antiderivative was successfully verified.

[In]

Int[Csc[x]^5/(I + Cot[x]),x]

[Out]

(I/2)*ArcTanh[Cos[x]] + (I/2)*Cot[x]*Csc[x] - Csc[x]^3/3

Rule 3501

Int[((d_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(d^2*
(d*Sec[e + f*x])^(m - 2)*(a + b*Tan[e + f*x])^(n + 1))/(b*f*(m + n - 1)), x] + Dist[(d^2*(m - 2))/(a*(m + n -
1)), Int[(d*Sec[e + f*x])^(m - 2)*(a + b*Tan[e + f*x])^(n + 1), x], x] /; FreeQ[{a, b, d, e, f}, x] && EqQ[a^2
+ b^2, 0] && LtQ[n, 0] && GtQ[m, 1] &&  !ILtQ[m + n, 0] && NeQ[m + n - 1, 0] && IntegersQ[2*m, 2*n]

Rule 3768

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Csc[c + d*x])^(n - 1))/(d*(n -
1)), x] + Dist[(b^2*(n - 2))/(n - 1), Int[(b*Csc[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1
] && IntegerQ[2*n]

Rule 3770

Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin {align*} \int \frac {\csc ^5(x)}{i+\cot (x)} \, dx &=-\frac {1}{3} \csc ^3(x)-i \int \csc ^3(x) \, dx\\ &=\frac {1}{2} i \cot (x) \csc (x)-\frac {\csc ^3(x)}{3}-\frac {1}{2} i \int \csc (x) \, dx\\ &=\frac {1}{2} i \tanh ^{-1}(\cos (x))+\frac {1}{2} i \cot (x) \csc (x)-\frac {\csc ^3(x)}{3}\\ \end {align*}

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Mathematica [B]  time = 0.10, size = 67, normalized size = 2.39 \[ \frac {1}{24} i \csc ^3(x) \left (6 \sin (2 x)+3 \sin (3 x) \log \left (\sin \left (\frac {x}{2}\right )\right )+9 \sin (x) \left (\log \left (\cos \left (\frac {x}{2}\right )\right )-\log \left (\sin \left (\frac {x}{2}\right )\right )\right )-3 \sin (3 x) \log \left (\cos \left (\frac {x}{2}\right )\right )+8 i\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[Csc[x]^5/(I + Cot[x]),x]

[Out]

(I/24)*Csc[x]^3*(8*I + 9*(Log[Cos[x/2]] - Log[Sin[x/2]])*Sin[x] + 6*Sin[2*x] - 3*Log[Cos[x/2]]*Sin[3*x] + 3*Lo
g[Sin[x/2]]*Sin[3*x])

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fricas [B]  time = 0.46, size = 97, normalized size = 3.46 \[ \frac {{\left (3 i \, e^{\left (6 i \, x\right )} - 9 i \, e^{\left (4 i \, x\right )} + 9 i \, e^{\left (2 i \, x\right )} - 3 i\right )} \log \left (e^{\left (i \, x\right )} + 1\right ) + {\left (-3 i \, e^{\left (6 i \, x\right )} + 9 i \, e^{\left (4 i \, x\right )} - 9 i \, e^{\left (2 i \, x\right )} + 3 i\right )} \log \left (e^{\left (i \, x\right )} - 1\right ) - 6 i \, e^{\left (5 i \, x\right )} + 16 i \, e^{\left (3 i \, x\right )} + 6 i \, e^{\left (i \, x\right )}}{6 \, {\left (e^{\left (6 i \, x\right )} - 3 \, e^{\left (4 i \, x\right )} + 3 \, e^{\left (2 i \, x\right )} - 1\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(x)^5/(I+cot(x)),x, algorithm="fricas")

[Out]

1/6*((3*I*e^(6*I*x) - 9*I*e^(4*I*x) + 9*I*e^(2*I*x) - 3*I)*log(e^(I*x) + 1) + (-3*I*e^(6*I*x) + 9*I*e^(4*I*x)
- 9*I*e^(2*I*x) + 3*I)*log(e^(I*x) - 1) - 6*I*e^(5*I*x) + 16*I*e^(3*I*x) + 6*I*e^(I*x))/(e^(6*I*x) - 3*e^(4*I*
x) + 3*e^(2*I*x) - 1)

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giac [B]  time = 0.65, size = 62, normalized size = 2.21 \[ -\frac {1}{24} \, \tan \left (\frac {1}{2} \, x\right )^{3} - \frac {1}{8} i \, \tan \left (\frac {1}{2} \, x\right )^{2} - \frac {-22 i \, \tan \left (\frac {1}{2} \, x\right )^{3} + 3 \, \tan \left (\frac {1}{2} \, x\right )^{2} - 3 i \, \tan \left (\frac {1}{2} \, x\right ) + 1}{24 \, \tan \left (\frac {1}{2} \, x\right )^{3}} - \frac {1}{2} i \, \log \left (\tan \left (\frac {1}{2} \, x\right )\right ) - \frac {1}{8} \, \tan \left (\frac {1}{2} \, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(x)^5/(I+cot(x)),x, algorithm="giac")

[Out]

-1/24*tan(1/2*x)^3 - 1/8*I*tan(1/2*x)^2 - 1/24*(-22*I*tan(1/2*x)^3 + 3*tan(1/2*x)^2 - 3*I*tan(1/2*x) + 1)/tan(
1/2*x)^3 - 1/2*I*log(tan(1/2*x)) - 1/8*tan(1/2*x)

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maple [B]  time = 0.30, size = 58, normalized size = 2.07 \[ -\frac {\tan \left (\frac {x}{2}\right )}{8}-\frac {\left (\tan ^{3}\left (\frac {x}{2}\right )\right )}{24}-\frac {i \left (\tan ^{2}\left (\frac {x}{2}\right )\right )}{8}+\frac {i}{8 \tan \left (\frac {x}{2}\right )^{2}}-\frac {1}{24 \tan \left (\frac {x}{2}\right )^{3}}-\frac {i \ln \left (\tan \left (\frac {x}{2}\right )\right )}{2}-\frac {1}{8 \tan \left (\frac {x}{2}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csc(x)^5/(I+cot(x)),x)

[Out]

-1/8*tan(1/2*x)-1/24*tan(1/2*x)^3-1/8*I*tan(1/2*x)^2+1/8*I/tan(1/2*x)^2-1/24/tan(1/2*x)^3-1/2*I*ln(tan(1/2*x))
-1/8/tan(1/2*x)

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maxima [B]  time = 0.36, size = 83, normalized size = 2.96 \[ -\frac {{\left (-\frac {6 i \, \sin \relax (x)}{\cos \relax (x) + 1} + \frac {6 \, \sin \relax (x)^{2}}{{\left (\cos \relax (x) + 1\right )}^{2}} + 2\right )} {\left (\cos \relax (x) + 1\right )}^{3}}{48 \, \sin \relax (x)^{3}} - \frac {\sin \relax (x)}{8 \, {\left (\cos \relax (x) + 1\right )}} - \frac {i \, \sin \relax (x)^{2}}{8 \, {\left (\cos \relax (x) + 1\right )}^{2}} - \frac {\sin \relax (x)^{3}}{24 \, {\left (\cos \relax (x) + 1\right )}^{3}} - \frac {1}{2} i \, \log \left (\frac {\sin \relax (x)}{\cos \relax (x) + 1}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(x)^5/(I+cot(x)),x, algorithm="maxima")

[Out]

-1/48*(-6*I*sin(x)/(cos(x) + 1) + 6*sin(x)^2/(cos(x) + 1)^2 + 2)*(cos(x) + 1)^3/sin(x)^3 - 1/8*sin(x)/(cos(x)
+ 1) - 1/8*I*sin(x)^2/(cos(x) + 1)^2 - 1/24*sin(x)^3/(cos(x) + 1)^3 - 1/2*I*log(sin(x)/(cos(x) + 1))

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mupad [B]  time = 0.23, size = 55, normalized size = 1.96 \[ -\frac {\mathrm {tan}\left (\frac {x}{2}\right )}{8}-\frac {\ln \left (\mathrm {tan}\left (\frac {x}{2}\right )\right )\,1{}\mathrm {i}}{2}-\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^2\,1{}\mathrm {i}}{8}-\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^3}{24}-\frac {{\mathrm {tan}\left (\frac {x}{2}\right )}^2-\mathrm {tan}\left (\frac {x}{2}\right )\,1{}\mathrm {i}+\frac {1}{3}}{8\,{\mathrm {tan}\left (\frac {x}{2}\right )}^3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(sin(x)^5*(cot(x) + 1i)),x)

[Out]

- tan(x/2)/8 - (log(tan(x/2))*1i)/2 - (tan(x/2)^2*1i)/8 - tan(x/2)^3/24 - (tan(x/2)^2 - tan(x/2)*1i + 1/3)/(8*
tan(x/2)^3)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\csc ^{5}{\relax (x )}}{\cot {\relax (x )} + i}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(x)**5/(I+cot(x)),x)

[Out]

Integral(csc(x)**5/(cot(x) + I), x)

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